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A virtual short-circuit (or simply virtual short) refers to a condition of a differential input amplifier such as an op-amp in which its noninverting and inverting inputs have almost the same voltage. This condition is called a virtual short-circuit because the differential inputs have the same voltage even though they are not connected together. This condition is met when a negative-feedback circuit is formed using a differential amplifier with a high open-loop gain.
When the input terminal on one side is grounded to GND as shown in the figure, it is sometimes called virtual ground.
These concepts are helpful for gain calculation.
You can conceptually understand a virtual short as follows.
Typical differential amplifiers have a finite output voltage. The output voltage of an op-amp is equal to its gain multiplied by a difference in voltage between the two inputs. The output voltage of a high-gain circuit becomes extremely large in the event of there being a large difference between the two input voltages. When the output voltage is finite, there is a very little difference in voltage (virtual short) between the two inputs.
Let’s consider this condition using simple calculations. Figure 1 shows a negative-feedback amplifier (inverting amplifier) using an op-amp.
Suppose that it is the ideal op-amp. Then, the following are true:
Because the input impedance is infinite, all of the current flowing through R_{1} (i1) flows through R_{2.
}i_{1} ＝ (V_{i} – V_{−}) / R1 = (V_{−} - V_{o}) / R_{2} (1)
The output voltage of the op-amp is given by the equation:
V_{o} = A_{V}(V_{+} - V_{−}) (2)
From Equation 1 and Equation 2, V_{+} is calculated as follows:
V_{+} ＝ {1 + (R_{1} + R_{2}) / (A_{V} * R_{1})} × V_{-} - R_{2} × V_{i} / (A_{V} × R_{1}) (3)
Because A_{V} is infinite, we obtain V_{＋} = V_{−}.
Hence, the voltage at the negative inverting input (V_{−}) is equal to the voltage at the grounded noninverting input (V_{+}).
This condition of the V_{−} input is called a virtual short.
Using this concept of a virtual short, the closed loop gain of this circuit can be calculated easily. We can conclude that no current flows to the V_{−} input since the V_{−} voltage is equal to GND and the input impedance is infinite. Since i_{1} = i_{2},
V_{i} / R_{2} = V_{o} / R_{1} (4)
Let the closed-loop gain of the inverting amplifier be G (= Vo/Vi). Then, G is calculated as R_{1}/R_{2}.
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