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What is the slew rate control function of eFuse IC (electronic fuses) intended to do? And how does it works?

When the output is turned on, an inrush current flows to charge the capacitor connected to the load side. If this current is too large, the overcurrent protection circuit may malfunction, making it impossible to start up, or overshooting may occur in the output voltage.
To prevent this, this function limits the inrush current and controls the slew rate at the rise of the output voltage.

As a result of the rush current flowing, Voltage drops occur in VIN.
By gradually raising VOUT, There is no impact on VIN.
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